If -1 is a zero of the polynomial p(x)=`"x"^{2}` -7x-8 , then the other zero is

(a) -8

(b) -7

(c) 1

(d) 8

(d) 8

**Explanation:**

Given,

p(x)=`"x"^{2}` -7x-8

Let, α = -1, and β be zeros of p(x) [α = -1 because -1 is zeros of p(x)]

Now, Product of zeroes = `"c"/"a"`

= -1`\times`β = `-8/1`

= β = 8

∴ other zero is 8

So, the correct answer is option (d) 8