If ABCD is a rectangle , find the values of x and y
(a) X=10,y=2
(b) X=12,y=8
(c) X=2,y=10
(d) X=20,y=0
(a) X=10,y=2
Explanation:
ABCD is a rectangle
So, AB = DC and DA = BC (opposite sides of rectangle)
x + y = 12 .....(1)
x - y = 8 .....(2)
Now, (1) + (2)
(x + y) + (x - y) = 12 + 8
2x = 20
x = `20/2`
x = 10
By putting x = 10 in (1)
x + y = 12
10 + y = 12
y = 12 - 10
y = 2
∴ x = 10 and y = 2