In the figure given below, AD=4cm,BD=3cm and CB=12 cm, then cotƟ equals

By Pythagoras theorem

`"AB"^{2}`=`"AD"^{2}`+`"BD"^{2}`

=`"AB"^{2}`=`"4"^{2}`+`"3"^{2}`

=`"AB"^{2}`= 16 + 9

=`"AB"^{2}`= 16 + 9

=`"AB"^{2}`= 25

=`"AB"^{2}`= `"5"^{2}`

∴ AB = 5

Now,

tan θ = `"AB"/"BC"`

tan θ = `"5"/"12"`

So,

cot θ = `12/5`

So, the correct answer is option (d) 12/5