A train running at 30 m/s is slowed uniformly to a stop in 44s . find the acceleration and stopping distance.

A train running at 30 m/s is slowed uniformly to a stop in 44s . find the acceleration and stopping distance.

A train running at 30 m/s is slowed uniformly to a stop in 44s . find the acceleration and stopping distance.





Given, Acceleration = -(30 m/s)/44s

= -0.682 m/s^2

stopping distance

= average velocity `\times` (stopping time)

= (15 m/s) `\times` 44 s

= 660 m/s

Thus, the acceleration and stopping distance = 660 m/s

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