A train running at 30 m/s is slowed uniformly to a stop in 44s . find the acceleration and stopping distance.
Given, Acceleration = -(30 m/s)/44s
= -0.682 m/s^2
stopping distance
= average velocity `\times` (stopping time)
= (15 m/s) `\times` 44 s
= 660 m/s
Thus, the acceleration and stopping distance = 660 m/s